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Question 1 of 100

Given the following snippet, what is the result of executing it?

try {
  System.out.println("A");
  throw new Exception();
} catch (Exception e) {
  System.out.println("B");
  throw new RuntimeException();
} finally {
  System.out.println("C");
}

(Choose one correct answer)

Prints A, B, throws a RuntimeException, and skips finally block.

Only prints A and B, then exits.

Compilation error.

Prints A, B, and C in that order, and then throws a RuntimeException.

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